Diket:
Balok
p = 20 cm
l = 9 cm
t = 14 cm
Ditanya: Lp?
Jawab:
Lp = 2 × ((p × l) + (p × t) + (l × t))
= 2 × ((20 × 9) + (20 × 14) + (9 × 14))
= 2 × (180 + 280 + 126)
= 2 × 586
= 1.172
-› PENYELESAIAN ‹-
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Diketahui :
Panjang = 20 cm
Lebar = 9 cm
Tinggi = 14 cm
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Ditanya :
Luas Permukaan ?
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Dijawab :
[tex] \sf \: Lp = 2 \times (p \times l + p \times t + l \times t)[/tex]
[tex] \sf \:Lp = 2 \times (20 \times 9 + 20 \times 14 \times 9 \times 14)[/tex]
[tex] \sf \: Lp = 2 \times (180 + 280 + 126)[/tex]
[tex] \sf \: Lp = 2 \times 586[/tex]
[tex] \sf \: Lp = 1.172 \: {cm}^{2}✓ [/tex]
Kesimpulan :
Luas Permukaan Balok adalah 1.172 cm²
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